Optimal. Leaf size=295 \[ \frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,1;m+2;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,1;m+2;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,2;m+2;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,2;m+2;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)} \]
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Rubi [A] time = 0.417643, antiderivative size = 295, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {961, 135, 133, 912} \[ \frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,1;m+2;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,1;m+2;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,2;m+2;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)}+\frac{(g x)^{m+1} (d+e x)^n \left (\frac{e x}{d}+1\right )^{-n} F_1\left (m+1;-n,2;m+2;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (m+1)} \]
Antiderivative was successfully verified.
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Rule 961
Rule 135
Rule 133
Rule 912
Rubi steps
\begin{align*} \int \frac{(g x)^m (d+e x)^n}{\left (a+c x^2\right )^2} \, dx &=\int \left (-\frac{c (g x)^m (d+e x)^n}{4 a \left (\sqrt{-a} \sqrt{c}-c x\right )^2}-\frac{c (g x)^m (d+e x)^n}{4 a \left (\sqrt{-a} \sqrt{c}+c x\right )^2}-\frac{c (g x)^m (d+e x)^n}{2 a \left (-a c-c^2 x^2\right )}\right ) \, dx\\ &=-\frac{c \int \frac{(g x)^m (d+e x)^n}{\left (\sqrt{-a} \sqrt{c}-c x\right )^2} \, dx}{4 a}-\frac{c \int \frac{(g x)^m (d+e x)^n}{\left (\sqrt{-a} \sqrt{c}+c x\right )^2} \, dx}{4 a}-\frac{c \int \frac{(g x)^m (d+e x)^n}{-a c-c^2 x^2} \, dx}{2 a}\\ &=-\frac{c \int \left (-\frac{\sqrt{-a} (g x)^m (d+e x)^n}{2 a c \left (\sqrt{-a}-\sqrt{c} x\right )}-\frac{\sqrt{-a} (g x)^m (d+e x)^n}{2 a c \left (\sqrt{-a}+\sqrt{c} x\right )}\right ) \, dx}{2 a}-\frac{\left (c (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n}\right ) \int \frac{(g x)^m \left (1+\frac{e x}{d}\right )^n}{\left (\sqrt{-a} \sqrt{c}-c x\right )^2} \, dx}{4 a}-\frac{\left (c (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n}\right ) \int \frac{(g x)^m \left (1+\frac{e x}{d}\right )^n}{\left (\sqrt{-a} \sqrt{c}+c x\right )^2} \, dx}{4 a}\\ &=\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{\int \frac{(g x)^m (d+e x)^n}{\sqrt{-a}-\sqrt{c} x} \, dx}{4 (-a)^{3/2}}+\frac{\int \frac{(g x)^m (d+e x)^n}{\sqrt{-a}+\sqrt{c} x} \, dx}{4 (-a)^{3/2}}\\ &=\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{\left ((d+e x)^n \left (1+\frac{e x}{d}\right )^{-n}\right ) \int \frac{(g x)^m \left (1+\frac{e x}{d}\right )^n}{\sqrt{-a}-\sqrt{c} x} \, dx}{4 (-a)^{3/2}}+\frac{\left ((d+e x)^n \left (1+\frac{e x}{d}\right )^{-n}\right ) \int \frac{(g x)^m \left (1+\frac{e x}{d}\right )^n}{\sqrt{-a}+\sqrt{c} x} \, dx}{4 (-a)^{3/2}}\\ &=\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,1;2+m;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,1;2+m;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},-\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}+\frac{(g x)^{1+m} (d+e x)^n \left (1+\frac{e x}{d}\right )^{-n} F_1\left (1+m;-n,2;2+m;-\frac{e x}{d},\frac{\sqrt{c} x}{\sqrt{-a}}\right )}{4 a^2 g (1+m)}\\ \end{align*}
Mathematica [F] time = 0.222908, size = 0, normalized size = 0. \[ \int \frac{(g x)^m (d+e x)^n}{\left (a+c x^2\right )^2} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.73, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( gx \right ) ^{m} \left ( ex+d \right ) ^{n}}{ \left ( c{x}^{2}+a \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{c^{2} x^{4} + 2 \, a c x^{2} + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{n} \left (g x\right )^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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